Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:49Z
ω = 2πf
\frac{12}{6} \sum_{i=1}^{n} i^{2}
97K
10ω² + 6ω + 2 = 0
ω = 2πf
\frac{8}{6} \sum_{i=1}^{n} i^{2}
452K
12z² + 3z + 1 = 0
\frac{3}{2} \sum_{i=1}^{n} i^{2}
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
96K