Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:23Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 9 4 ; 1 10 | = 86
97K
10ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
ω = 2πf
det| 5 9 ; 0 6 | = 30
224K
det| 2 7 ; 7 3 | = -43
33K
det| 7 9 ; 1 8 | = 47
96K