Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:50Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 9 4 ; 1 10 | = 86
97K
10ω² + 6ω + 2 = 0
ω = 2πf
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
452K
12z² + 3z + 1 = 0
det| 4 2 ; 1 5 | = 18
155K
det| 7 1 ; 7 8 | = 49
96K