Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 17:38Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
369K
det| 7 4 ; 4 8 | = 40
133K
\lim_{y\to 0} \frac{\sin y}{y} = 1
ΔS ≥ 0
5n² + 6n + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
98K
CH₄ + 2O₂ → CO₂ + 2H₂O
126K