Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:05Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12γ² + 5γ + 2 = 0
\frac{8}{6} \sum_{i=1}^{n} i^{2}
354K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
224K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
452K
det| 7 6 ; 6 8 | = 20
det| 4 8 ; 3 5 | = -4
33K
\frac{11}{1} \sum_{i=1}^{n} i^{2}