Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:11Z
ω = 2πf
10ω² + 6ω + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
366K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
224K
det| 4 8 ; 3 5 | = -4
452K
12z² + 3z + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
33K
det| 6 6 ; 2 7 | = 30
273K
det| 7 4 ; 4 8 | = 40
245K