Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 05:07Z
det| 11 5 ; 5 12 | = 107
det| 4 8 ; 3 5 | = -4
369K
∑_{k=1}^{n} k = n(n+1)/2
133K
d/dz [z^3] = 3z^2
10θ² + 5θ + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
404K
N₂ + 3H₂ ⇌ 2NH₃
d/dx [x^9] = 9x^8
det| 7 4 ; 4 8 | = 40
24K
ω = 2πf
∇²θ = 0
5ω² + 3ω + 0 = 0