Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 05:11Z
det| 11 5 ; 5 12 | = 107
∑_{k=1}^{n} k = n(n+1)/2
369K
d/dz [z^3] = 3z^2
∫₀^∞ e^(-θ²) dθ = √π / 2
398K
10θ² + 5θ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
d/dx [x^9] = 9x^8
∑_{k=1}^{n} k = n(n+1)/2
24K
ω = 2πf