Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:55Z
ω = 2πf
10ω² + 6ω + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
354K
ω = 2πf
12z² + 3z + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
96K
12t² + 9t + 1 = 0
\frac{8}{6} \sum_{i=1}^{n} i^{2}
213K