Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 20:53Z
det| 6 5 ; 3 7 | = 27
∑_{k=1}^{n} k = n(n+1)/2
97K
d/dn [n^11] = 11n^10
det| 5 6 ; 4 6 | = 6
354K
det| 6 6 ; 2 7 | = 30
det| 9 4 ; 1 10 | = 86
224K
E = mc²
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
96K