Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 20:19Z
det| 6 5 ; 3 7 | = 27
det| 9 4 ; 1 10 | = 86
97K
d/dn [n^11] = 11n^10
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 6 6 ; 2 7 | = 30
det| 5 9 ; 0 6 | = 30
224K
E = mc²
det| 1 1 ; 5 2 | = -3
155K
∫₀^∞ e^(-ψ²) dψ = √π / 2
33K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
96K