Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:57Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-α²) dα = √π / 2
129K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
97K
12γ² + 5γ + 2 = 0
λ = h/p
det| 7 6 ; 6 8 | = 20
\frac{2}{2} \sum_{i=1}^{n} i^{2}
155K
\frac{11}{1} \sum_{i=1}^{n} i^{2}