Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:23Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 11 9 ; 0 12 | = 132
97K
10ω² + 6ω + 2 = 0
det| 5 2 ; 3 6 | = 24
354K
ω = 2πf
det| 7 4 ; 4 8 | = 40
224K
12z² + 3z + 1 = 0
det| 4 7 ; 2 5 | = 6
155K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
11z² + 7z + 1 = 0
12t² + 9t + 1 = 0