Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:57Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 6 6 ; 3 7 | = 24
97K
10ω² + 6ω + 2 = 0
det| 9 4 ; 1 10 | = 86
354K
ω = 2πf
det| 3 1 ; 7 4 | = 5
452K
12z² + 3z + 1 = 0
\frac{3}{1} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-α²) dα = √π / 2
96K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
273K
12t² + 9t + 1 = 0