Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 22:37Z
\frac{6}{4} \sum_{i=1}^{n} i^{2}
∂α/∂ω = 9α
∑_{k=1}^{n} k = n(n+1)/2
366K
\frac{4}{6} \sum_{i=1}^{n} i^{2}
\frac{8}{6} \sum_{i=1}^{n} i^{2}
224K
\frac{6}{3} \sum_{i=1}^{n} i^{2}
33K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
245K