Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:49Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
97K
10ω² + 6ω + 2 = 0
ω = 2πf
det| 7 4 ; 4 8 | = 40
224K
det| 2 7 ; 7 3 | = -43
452K
CH₄ + 2O₂ → CO₂ + 2H₂O
96K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
273K