Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-18 19:57Z
10z² + 2z + 2 = 0
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
405K
\frac{5}{1} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
390K
d/dβ [β^2] = 2β^1
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
139K
∑_{k=1}^{n} k = n(n+1)/2
304K
iħ ∂ψ/∂t = Ĥψ
det| 7 4 ; 4 8 | = 40
479K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2