Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:18Z
ω = 2πf
10ω² + 6ω + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
354K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
452K
12z² + 3z + 1 = 0
\frac{3}{1} \sum_{i=1}^{n} i^{2}
12t² + 9t + 1 = 0
det| 7 5 ; 4 8 | = 36