Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 20:28Z
det| 6 5 ; 3 7 | = 27
∑_{k=1}^{n} k = n(n+1)/2
97K
d/dn [n^11] = 11n^10
∑_{k=1}^{n} k = n(n+1)/2
354K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
366K
det| 6 6 ; 2 7 | = 30
E = mc²
det| 7 4 ; 4 8 | = 40
245K
det| 2 4 ; 4 3 | = -10
213K