Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:04Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-α²) dα = √π / 2
97K
12γ² + 5γ + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
354K
λ = h/p
det| 5 7 ; 2 6 | = 16
224K
det| 7 6 ; 6 8 | = 20
det| 7 4 ; 4 8 | = 40
155K
\frac{11}{1} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
273K