Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:08Z
12t² + 1t + 5 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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d/dx [x^11] = 11x^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dα [α^3] = 3α^2
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
det| 4 1 ; 3 5 | = 17
11α² + 8α + 2 = 0