Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-18 22:29Z
∇²β = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
339K
7z² + 9z + 4 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
311K
d/dz [z^1] = 1z^0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
328K
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
304K
\frac{7}{3} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
78K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
221K