Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 20:30Z
det| 6 5 ; 3 7 | = 27
∑_{k=1}^{n} k = n(n+1)/2
97K
d/dn [n^11] = 11n^10
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 6 6 ; 2 7 | = 30
det| 5 9 ; 0 6 | = 30
224K
E = mc²
det| 11 9 ; 0 12 | = 132
155K
det| 7 4 ; 4 8 | = 40
273K