Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-18 19:54Z
10z² + 2z + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
192K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
339K
λ = h/p
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
405K
\frac{5}{1} \sum_{i=1}^{n} i^{2}
d/dβ [β^2] = 2β^1
iħ ∂ψ/∂t = Ĥψ
\frac{4}{6} \sum_{i=1}^{n} i^{2}
479K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
78K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 7 4 ; 4 8 | = 40
221K