Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:04Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
12γ² + 5γ + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
366K
λ = h/p
\frac{2}{2} \sum_{i=1}^{n} i^{2}
224K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
33K