Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 05:17Z
det| 11 5 ; 5 12 | = 107
∑_{k=1}^{n} k = n(n+1)/2
133K
d/dz [z^3] = 3z^2
10θ² + 5θ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
404K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
98K
det| 1 1 ; 5 2 | = -3
396K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
24K