Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 05:04Z
det| 11 5 ; 5 12 | = 107
∑_{k=1}^{n} k = n(n+1)/2
369K
det| 4 2 ; 1 5 | = 18
133K
d/dz [z^3] = 3z^2
det| 7 4 ; 4 8 | = 40
398K
10θ² + 5θ + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
98K
∑_{k=1}^{n} k = n(n+1)/2
396K