Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:13Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
97K
10ω² + 6ω + 2 = 0
∫₀^∞ e^(-α²) dα = √π / 2
366K
ω = 2πf
det| 7 9 ; 1 8 | = 47
224K
∑_{k=1}^{n} k = n(n+1)/2
452K
12z² + 3z + 1 = 0
det| 7 4 ; 4 8 | = 40
33K