Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 20:13Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
369K
det| 4 2 ; 3 5 | = 14
det| 9 1 ; 7 10 | = 83
264K
F = ma
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 9 4 ; 1 10 | = 86
98K
12α² + 1α + 6 = 0
det| 10 6 ; 4 11 | = 86
det| 7 9 ; 7 8 | = -7
6ψ² + 7ψ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂