Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:09Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
10ω² + 6ω + 2 = 0
ω = 2πf
12z² + 3z + 1 = 0
\frac{3}{1} \sum_{i=1}^{n} i^{2}
12t² + 9t + 1 = 0
det| 5 7 ; 2 6 | = 16
245K
det| 7 5 ; 4 8 | = 36
CH₄ + 2O₂ → CO₂ + 2H₂O
∂n/∂β = 6n