Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:58Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
97K
10ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
354K
det| 9 4 ; 1 10 | = 86
366K
ω = 2πf
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
452K
12z² + 3z + 1 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
33K