Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:57Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-α²) dα = √π / 2
129K
12γ² + 5γ + 2 = 0
\frac{3}{2} \sum_{i=1}^{n} i^{2}
354K
λ = h/p
det| 7 4 ; 4 8 | = 40
452K
det| 7 6 ; 6 8 | = 20
\frac{11}{1} \sum_{i=1}^{n} i^{2}
\frac{12}{6} \sum_{i=1}^{n} i^{2}
96K