Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 17:09Z
det| 7 4 ; 2 8 | = 48
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
129K
E = mc²
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-θ²) dθ = √π / 2
224K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
273K
d/dy [y^11] = 11y^10
245K