Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 12:43Z
11θ² + 3θ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
369K
∑_{k=1}^{n} k = n(n+1)/2
133K
∂γ/∂θ = 5γ
12α² + 6α + 2 = 0
det| 7 4 ; 4 8 | = 40
404K
CH₄ + 2O₂ → CO₂ + 2H₂O
271K
∑_{k=1}^{n} k = n(n+1)/2
346K