Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 06:47Z
9ω² + 4ω + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
369K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 3 3 ; 4 4 | = 0
264K
det| 10 5 ; 5 11 | = 85
det| 7 1 ; 7 8 | = 49
271K
ΔS ≥ 0
det| 9 4 ; 1 10 | = 86
98K
∇²θ = 0
ω = 2πf
∫₀^∞ e^(-ψ²) dψ = √π / 2
126K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}