Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 17:36Z
det| 7 4 ; 2 8 | = 48
det| 9 4 ; 1 10 | = 86
97K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
354K
det| 4 4 ; 5 5 | = 0
366K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-ψ²) dψ = √π / 2
33K