Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:29Z
ω = 2πf
10ω² + 6ω + 2 = 0
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
452K
12z² + 3z + 1 = 0
\frac{3}{1} \sum_{i=1}^{n} i^{2}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
273K
12t² + 9t + 1 = 0
det| 7 5 ; 4 8 | = 36