Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:08Z
ω = 2πf
10ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
ω = 2πf
det| 2 6 ; 0 3 | = 6
224K
det| 9 9 ; 5 10 | = 45
155K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
33K
det| 7 4 ; 4 8 | = 40
245K