Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:26Z
ω = 2πf
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
97K
10ω² + 6ω + 2 = 0
ω = 2πf
\binom{n}{k} = \frac{n!}{k!(n-k)!}
224K
12z² + 3z + 1 = 0
\frac{3}{1} \sum_{i=1}^{n} i^{2}
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
273K
det| 7 4 ; 4 8 | = 40
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