Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 16:26Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-x²) dx = √π / 2
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∑_{k=1}^{n} k = n(n+1)/2
452K
N₂ + 3H₂ ⇌ 2NH₃
det| 4 2 ; 1 5 | = 18
155K
det| 5 6 ; 7 6 | = -12
33K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
96K
∇²β = 0
F = G m₁m₂ / r²