Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:09Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12γ² + 5γ + 2 = 0
∫₀^∞ e^(-α²) dα = √π / 2
354K
\frac{8}{6} \sum_{i=1}^{n} i^{2}
366K
λ = h/p
det| 6 6 ; 2 7 | = 30
452K
det| 7 6 ; 6 8 | = 20
\frac{3}{2} \sum_{i=1}^{n} i^{2}
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
96K
\frac{12}{6} \sum_{i=1}^{n} i^{2}
245K