Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 20:05Z
det| 6 5 ; 3 7 | = 27
det| 3 9 ; 1 4 | = 3
129K
d/dn [n^11] = 11n^10
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 6 6 ; 2 7 | = 30
det| 5 6 ; 4 6 | = 6
224K
det| 2 6 ; 0 3 | = 6
452K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
33K
2H₂ + O₂ → 2H₂O