Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 17:37Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
133K
\lim_{y\to 0} \frac{\sin y}{y} = 1
det| 4 8 ; 3 5 | = -4
398K
ΔS ≥ 0
det| 3 1 ; 7 4 | = 5
404K
det| 9 4 ; 1 10 | = 86
271K
5n² + 6n + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
396K
∑_{k=1}^{n} k = n(n+1)/2
346K
∫₀^∞ e^(-ψ²) dψ = √π / 2
126K