Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:03Z
12t² + 1t + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
133K
d/dx [x^11] = 11x^10
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
404K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
396K
d/dα [α^3] = 3α^2
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2