Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 22:56Z
\frac{6}{4} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
97K
∂α/∂ω = 9α
\frac{4}{6} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
452K
ΔS ≥ 0
det| 7 4 ; 4 8 | = 40
33K
F = G m₁m₂ / r²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
96K
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
245K
10x² + 7x + 7 = 0
9β² + 5β + 4 = 0