Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:27Z
ω = 2πf
10ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
354K
ω = 2πf
12z² + 3z + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
12t² + 9t + 1 = 0
det| 7 4 ; 4 8 | = 40
245K