Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:48Z
ω = 2πf
10ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
ω = 2πf
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
224K
det| 2 7 ; 7 3 | = -43
452K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
33K
det| 7 6 ; 1 8 | = 50
96K
det| 9 4 ; 1 10 | = 86
273K