Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 17:18Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
369K
\lim_{y\to 0} \frac{\sin y}{y} = 1
∑_{k=1}^{n} k = n(n+1)/2
264K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
271K
5n² + 6n + 0 = 0
7φ² + 5φ + 7 = 0