Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:25Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 9 1 ; 7 10 | = 83
97K
10ω² + 6ω + 2 = 0
det| 5 7 ; 2 6 | = 16
366K
ω = 2πf
det| 9 4 ; 1 10 | = 86
452K
∑_{k=1}^{n} k = n(n+1)/2
155K
∑_{k=1}^{n} k = n(n+1)/2
33K