Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:43Z
12t² + 1t + 5 = 0
d/dx [x^11] = 11x^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
98K
\frac{3}{2} \sum_{i=1}^{n} i^{2}
396K